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A change jar holds 36 nickels, 30 dimes, and 15 quarters. What is the probability that a nickel will be drawn first and then a dime (without replacement)?
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total number = 45+36 = 81
P(N, D) = (36/81) x (30/ 80)
assuming the coins are the same size and all the other things, even though thats not possible
You have to assume they are blindfolded and wearing thick gloves and cannot gauge the weights of the coins
thank you for the help :)
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= 1/6
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