Question

Ok so, Find the coordinates of the points of intersection.
X-3=0
X^2 + Y^2 = 36
No idea what to do but they tell me the answer is
3, 3 root 3. 0.0?
Please help.

Answer 1

The first equation is a vertical line at x = 3.
The second equation is a circle centered at the origin with a radius of 6.

Answer 2

x-3=0
x=3

Put it in 2nd equation:
\[3^2+y^2=36\]
\[y^2=27\]
\[y=\pm \sqrt{27}=\pm3\sqrt3\]

Answer 3

(3, 3 root 3)
(3, -(3 root 3))