Question

can someone show me how to take the partial derivative of tan^-1[(2xy)/(x^2-y^2)] with respect to X. could you please show me the steps so I can do the partial with respect to y on my own. I understand how to do simple partials, however, I am getting confused with this one

Answer 1

\[\text{ArcTan}\left[\frac{(2\text{xy})}{x^2-y^2}\right]\]

Answer 2

Chain rules ; First Arctan[], then innner function