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7^3x-17=2,401. solve and express each side as a power of the same base and then equating exponents
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\[7^{3x+17}=2,401\]
what's 7^2, 7^3, 7^4
7^2=49 7^3=343 7^4=2401 So we may rewrite 2401 as 7^4
\[7^{3x+17}=7^4\]
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