Question

how do you factor out x^3+2x^2-16x-32=0?

Answer 1

x^2(x+2)-16(x+2)=0
(x+2)(x^2-16)=0
(x+2)(x-4)(x+4)=0

Answer 2

x=-2,4,-4

Answer 3

factor by grouping maybe? lol

Answer 4

\[x^{3}+2x^{2}-16x-32=0\]\[(x^{3}+2x^{2})-(16x+32)=0\]\[x^{2}(x+2)-16(x+2)=0\]etc...