Question

x^2+3x-4=0
solve
medals will be awarded

Answer 1

(x-1)(x+4)

Answer 2

so x=1 and x=-4

Answer 3

thanks guys.

Answer 4

\[x^2+3x-4=0\]
\[x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-3 \pm \sqrt {9+16}}{2}=1;-4\]