What is the equation in point-slope form of the line passing through (-2, 1) and (4, 13)? (1 points)
Question 15 options:
1) y - 1 = -2(x - 4)
2) y - 1 = 2(x + 2)
3) y - 13 = -2(x + 2)
4) y - 13 = 2(x + 4)

Question

What is the equation in point-slope form of the line passing through (-2, 1) and (4, 13)? (1 points)
Question 15 options:
	1)	y - 1 = -2(x - 4)
	2)	y - 1 = 2(x + 2)
	3)	y - 13 = -2(x + 2)
	4)	y - 13 = 2(x + 4)

anonymous · Answer

2)

myininaya · Answer

$$m=\frac{y-y_1}{x-x_1}$$

so

$$(x-x_1)m=y-y_1$$

so what is m?

$$m=\frac{13-1}{4-(-2)}=\frac{12}{6}=2$$

y-1=2(x-(-2))
y-1=2(x+2)