Question

Show that the equation x^2 + y^2 = 4z + 3 has no solution in integers. Hint: Recall that an even number is of the form 2n and an odd number is of the form 2n + 1. Consider all possible cases for x and y even or odd

Answer 1

We had this one yesterday, posted by emerald I think.

Answer 2

Let me see if I can find it....

Answer 3

I just found it thanks :)

Answer 4

Ok, that should get u on the way