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OpenStudy (anonymous):
sqr. of 5y - 3x = x - 6y get the dy/dx of this please.
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OpenStudy (anonymous):
1/2(5y-3x)^-1/2(5y'-3)=1-6y'
OpenStudy (anonymous):
Now we have to isolate y', usually on left side
OpenStudy (anonymous):
show me how to isolate y" please
OpenStudy (anonymous):
y'
OpenStudy (anonymous):
my answer is \[y' =2 \sqrt{5y-3x} -5y +3 / 6\]
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