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(x+3)(x-13)(x+2)>0
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I want to check my answer that i have here
zeros are at -3,-2 and 13
so -3<x<-2 or x>13 is correct
it will be negative on \[(-\infty,-3)\] positive on \[(-3,-2)\] negative on \[(-2,13)\] and then positive on \[(13,\infty)\]
yeas what you wrote!
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ok i wanted to check thanks
ye
x2+78
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