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Mathematics 21 Online
OpenStudy (anonymous):

(x+3)(x-13)(x+2)>0

OpenStudy (anonymous):

I want to check my answer that i have here

OpenStudy (anonymous):

zeros are at -3,-2 and 13

OpenStudy (anonymous):

so -3<x<-2 or x>13 is correct

OpenStudy (anonymous):

it will be negative on \[(-\infty,-3)\] positive on \[(-3,-2)\] negative on \[(-2,13)\] and then positive on \[(13,\infty)\]

OpenStudy (anonymous):

yeas what you wrote!

OpenStudy (anonymous):

ok i wanted to check thanks

OpenStudy (anonymous):

ye

OpenStudy (anonymous):

x2+78

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