I'm trying to sketch y=f(x-2)+3 and y=f(x+1)-4 for f(x)=e^x.... then isn't it supposed to be y=(e-2)^x+3 and y=(e+1)^x-4??? but after I sketched these two graphs in my calculator it wasn't the same as the answers. Also, what will f(x)=1/x be for those two equations?

Question

anonymous · Answer

$$f(x-2)+3 = e^{x-2} + 3 $$

anonymous · Answer

you replace x with (x-2) , similiarly for the other one

anonymous · Answer

the +3 shifts the graph up 3units

anonymous · Answer

and the e^(x-2) , is e^x delayed by 2units

anonymous · Answer

so you take e^x , move it right 2units and up 3units