Question

Me. Cooper invested a sum of money at 6%. He invested a second sum, $150 more than the first 3%. If his total annual income was $54, how much did he invest at 3%?

Answer 1

a = b-e

ax +by = i

(b-e)x + by = i

bx -ex +by = i

b(x+y) = i + ex

sum @ 3% = (54 + 150(.06))/(.06 + .03) if i see it right, have to dbl chk

Answer 2

700@ 3% is what I get

700(.03) + 550(.06) = 54

21 + 33 = 54

54 = 54

Answer 3

Kk ty