Mathematics
6 Online
OpenStudy (anonymous):
please help <3 last test ever :) only 10 question so please help !
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
OpenStudy (anonymous):
thanks <3
OpenStudy (bahrom7893):
is this really the last one? xD let me take a look
OpenStudy (bahrom7893):
A = initial amount = 3000
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OpenStudy (anonymous):
yes i believe so .
OpenStudy (bahrom7893):
P = Ae^(kt)
P = 3000e^(kt)
OpenStudy (bahrom7893):
P(6) = 3,600
3600=3000e^(k*6)
OpenStudy (bahrom7893):
36 = 30e^(6k)
6 = 5e^(6k)
OpenStudy (bahrom7893):
take Ln on both sides:
Ln6 = ln[5e^(6k)]
use Ln properties to simplify
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OpenStudy (bahrom7893):
Ln6 = Ln5 + lne^(6k)
ln6 = ln5 + 6k(lne)
ln6 - ln5 = 6k since lne =1
OpenStudy (bahrom7893):
6k = 0.1823
OpenStudy (bahrom7893):
k = 0.1823/6 = 0.03
OpenStudy (bahrom7893):
Now put that back into P:
P = 3000e^(kt)
P = 3000e^(0.03t)
Now what is this equal to after 13 hours?
OpenStudy (bahrom7893):
P(13) = 3000e^(0.03*13) = 4430.94 to the nearest whole that's like 4431
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OpenStudy (amistre64):
you got to what: ln(P/A)/t = k right?
OpenStudy (bahrom7893):
I can't break this down any more than this..
OpenStudy (anonymous):
sorry i was in the bathroom and yes i understand :)
OpenStudy (anonymous):
yea omg i get it :) it was correct :D
OpenStudy (anonymous):
so all you do is replacing :) what u kno.
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OpenStudy (bahrom7893):
yea
OpenStudy (anonymous):
thanks :) u wanna help me with the other 10 or no :( ?
OpenStudy (anonymous):
OpenStudy (bahrom7893):
work this out posting the steps here, what do u do first?
OpenStudy (bahrom7893):
use initial pop = 197mln
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OpenStudy (anonymous):
ok give me a sec :) im gonna try to solve it :)