Question

Write the slope-intercept equation for the line that passes through (14, -2) and is perpendicular to 7x – 10y = 18 Please show all of your work

Answer 1

the slope of the equation 7x-10y=18 is
-10y=-7x+18
y=(7/10)x-18/7
so slope is 7/10
then because its perpendicular then the slope of the other line is
-10/7
so slope intercept equation is
y=(-10/7)x+b...... then solve for b by plugging in the point (14,-2) for x and y
-2=-20+b.... so b=18
and answer is y=(-10/7)x+18

Answer 2

y=7/10x-18/7
7/10 = slope
7/10*x=-1
x=-10/7
-10/7(x,y)(14,-2)
change in y
-------
change in x
y+2 = -10/7
----
x-14
7(y+2)=-10(x-14)
7y+14=-10x+140
y=-10/7x+20

Answer 3

it should be +18 not 20

Answer 4

y=-10/7x+18