Question

use substitution to solve the system of equations.
y=x+1
8x-4y=0

Answer 1

y=x+1 --------(1)
8x-4y=0 --------(2)

in the second equation (2) substitute the value of y from (1)

8x - 4(x+1) = 0
8x - 4x -4 = 0
4x = 4
x = 4/4
x = 1

now substitute x = 1 in equation (1)
y = 1 + 1
y = 2

so x=1 and y=2 is the solution