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Evaluate the integral by making the given substitution.http://www.webassign.net/cgi-bin/symimage.cgi?expr=int%20e%2A%2A%28-2%20x%29%20text%28%20%29%20dx%2C%20text%28%20%29%20u%20%3D%20-2%20x
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\[\int\limits e^u du= e^u\] Substitute back in
du=-2 dx so you will have -1/2 in front of integral
keep in mind that if u=-2x then: du=-2dx or dx=-1/2 du
ok thanks guys : )
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