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Mathematics 23 Online
OpenStudy (anonymous):

(Diff Eq) I don't quite understand this from my textbook example: (x^2 + u^2 x^2)dx + (x^2 + ux^2) [u dx + x du ] = 0 ----> x^2 (1+u)dx + x^3 (1-u)du = 0 I'm totally missing something here.

OpenStudy (anonymous):

That last term should be (x^2 - ux^2)[u dx + x du]

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