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\[3^{2008}+4^{2009}\] can be written as product of two positive integers each of which is larger than \[2009^{?}\]
sry 2009^182
I know solutin fur this one also so you can ask me if u want
let me think about it for a bit...right now i have no clue though lol, i will ask about eventually though, seems really interesting o.O
yeah....i dont see it >.< how would you even start such a problem?
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wait
the even diggit part is irrelevant
oh wow, ive never seen that factorization before. if someone knew about that, then the problem seems kinda obvious (since there is one more 4 than 3's). i'll have to take note of that >.>
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