Question

A plane passes through the points (6,-4,3) and (0,4,-3). The sum of its intercepts on the coordinate axes is zero. Its distance from the origin is

Answer 1

x/a + y/b + z/c =1

a + b + c = 0

plug in the two pts to get two more eqns

3 variables and 3 equations, find a b and c

Answer 2

please explain me the whole answer him1618 and please with every step explained

Answer 3

x/a + y/b + z/c =1

this is the intercept form of a plane

sum of intercepts is zero so

a+b+c=0

Answer 4

Okkkk

Answer 5

Then

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Answer 6

now plug in (6,4,3) into ur plane

6/a + 4/b + 3/c = 1

plug in (0,4,-3) now

4/b -3/c = 1

3 variables and three eqns

Answer 7

solve them

Answer 8

Let me see if I can solve them

Answer 9

Where is the third equation ?