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OpenStudy (vishweshshrimali5):
A plane passes through the points (6,-4,3) and (0,4,-3). The sum of its intercepts on the coordinate axes is zero. Its distance from the origin is
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OpenStudy (anonymous):
x/a + y/b + z/c =1 a + b + c = 0 plug in the two pts to get two more eqns 3 variables and 3 equations, find a b and c
OpenStudy (vishweshshrimali5):
please explain me the whole answer him1618 and please with every step explained
OpenStudy (anonymous):
x/a + y/b + z/c =1 this is the intercept form of a plane sum of intercepts is zero so a+b+c=0
OpenStudy (vishweshshrimali5):
Okkkk
OpenStudy (vishweshshrimali5):
Then ?
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OpenStudy (anonymous):
now plug in (6,4,3) into ur plane 6/a + 4/b + 3/c = 1 plug in (0,4,-3) now 4/b -3/c = 1 3 variables and three eqns
OpenStudy (anonymous):
solve them
OpenStudy (vishweshshrimali5):
Let me see if I can solve them
OpenStudy (vishweshshrimali5):
Where is the third equation ?
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