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OpenStudy (anonymous):
Given the function K described by K(x)=x+1,find each of the following k(0)=?
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OpenStudy (anonymous):
plug in zero everywhere you see x
OpenStudy (anonymous):
k(0)=1
OpenStudy (anonymous):
k(0)=0+1
OpenStudy (anonymous):
k(-3)=?
OpenStudy (anonymous):
everywhere you see x plug in -3
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OpenStudy (anonymous):
-2
OpenStudy (anonymous):
right
OpenStudy (anonymous):
k(-18)=?
OpenStudy (anonymous):
plug in -18 everywhere you see an x
OpenStudy (anonymous):
hey do just as lagrange said put -18 instead of x
f(-18)=? u tell me
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OpenStudy (anonymous):
do you see a pattern??
OpenStudy (anonymous):
no I dont
OpenStudy (anonymous):
f(-18)= -18 +1 now tell the answer
OpenStudy (anonymous):
-17?
OpenStudy (anonymous):
right
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OpenStudy (anonymous):
k(y+4)=?
OpenStudy (anonymous):
put y+4 instead of x in the eq f(x) = x +1
try and tell the answer :)
OpenStudy (anonymous):
f(y+4)=y+4+1
OpenStudy (anonymous):
5y?
OpenStudy (anonymous):
you have to show me I wont answer u nemore
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OpenStudy (anonymous):
then dont
OpenStudy (anonymous):
Im not begging you
OpenStudy (anonymous):
ur not learning , i want u to learn . this is important tc
OpenStudy (anonymous):
put the value instead of x if question say put d in f(x)=x+1
then put d intd of x
u will get f(d)=d+1
OpenStudy (anonymous):
I do not understand. But you do not have to help me if you do not want to. I am going into a profession that this will never serve a purpose
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