Question

UPLOADED

Answer 1

Have you studied recurrence relations?

Answer 2

I AM not quite sure y

Answer 3

You start with the base case, a_1 = 1

So we want the next term:
\[a_n = 2a_{n-1}\]
So we have
\[a_2 = 2a_{2-1} = 2a_{1} = 2\cdot1 = 2\]

Can you do the rest?

Answer 4

For the next term we have:
\[a_3 = 2a_{3-1} = 2a_2 = 2\cdot2 = 4\]

Answer 5

THANS MATE