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Mathematics 8 Online
OpenStudy (anonymous):

Divide and state any restrictions on the variables. (k+2)/(k-6)÷(k+3)/(k^2-k-30)

OpenStudy (anonymous):

\[(k+2)/(k-6)\div(k+3)/(k^2-k-30)\]factor denominator of left term, take reciprocal and multiply\[(k+2)/(k-6)\times((k-6)(k+5))/(k+3)\]cancel factor of (k-6) in numerator and denominator\[((k+2)(k+5))/(k+3)\]\[k \neq6\]

OpenStudy (anonymous):

k cannot equal -3

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