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a) If y(x) = (x^2 + x-1) * (x-1)^4 *(x-2)^2, then d^4 y/dx^4 at x = 1 is (b)If y(x) = (1+x^2)^-1 , then d^4y/dx^4 at x=0 is (c) If f is differentiable f(2) = 6 and f'(2) = 1/48, then lim x--> 2 integration limits 0 to f(x) t^3/(x-2) dt is (d) If {x} = x - [x], then integration under limits 0 to 64 {x^1/3} dx is
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