Question

Evaluate the function at the given values for x: f(x) = log2 x + 1 Write your answer in ordered pair form in the blank. Ex: (1/4, ), (1, ), (4, )

Answer 1

\[f(x)=\log_2(x)+1\] yes?

Answer 2

yes

Answer 3

\[f(1)=\log_2(1)+1=0+1=2\]

Answer 4

the reason
\[\log_2(1)=0\] is because
\[2^0=1\]

Answer 5

\[\log_2(4)+1=2+1=3\]

Answer 6

and again
\[\log_2(4)=2\] because
\[2^2=4\]

Answer 7

finally
\[\log_2(\frac{1}{4})+1=-2+1=-1\]

Answer 8

because
\[2^{-2}=\frac{1}{2^2}=\frac{1}{4}\]

Answer 9

I'm sorry, I dont understand where the ordered pair is.

Answer 10

is it (1/4, -1)?