Question

g(x)=(1-2x)^2(x-3), g'(x)= (1-2x)^2-4(1-2x)(x-3), what is g''(x) equalls to?

Answer 1

g''x = 24x - 32

Answer 2

\[g'(x)=1-4x-4x^2+4x+12+8x^2-24x=12x^2-32x+1\]\[g''(x)=24x-32\]

Answer 3

what are the y and x intercepts of g(x)=(1-2x)^2(x-3)?

Answer 4

To find the y-intercept, set replace x with 0 in the equation, then solve for g(x)
To find the x-intercept, replace g(x) with 0 in the equation then solve for x.

Answer 5

how can i find where the function is increasing and decreasing?

Answer 6

You have to graph it

Answer 7

i need to show my calculations