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Mathematics 7 Online
OpenStudy (anonymous):

solve 0.7x+8

OpenStudy (anonymous):

0.7x+8</1.1x-3 [subtract 0.7x from both] 8</0.4x-3 [add 3 to both] 11</0.4x [divide both by 0.4 or better still multiply both by 4/10] 44/10 <x [simplify] 22/5x

OpenStudy (anonymous):

what symbol would you use?

OpenStudy (anonymous):

Sorry my mistype 22/5 <x

OpenStudy (anonymous):

0.7x+8 ≤1.1x-3 so 22/5 is what you got for this

OpenStudy (anonymous):

22/5 <x yes [but you have just type 'less than or equal to']

OpenStudy (anonymous):

what is the integer for your answer?

OpenStudy (anonymous):

ok 22/5 = 4 and 2/5

OpenStudy (anonymous):

so integer part is 4

OpenStudy (anonymous):

decimal?

OpenStudy (anonymous):

decimal ok 4.4

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