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Find k if 8! = 6!k.
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please help
8*7
\[8=8\times 7 \times 6!\]
Where's the algebra?
oops i meant to write \[8!=8\times 7 \times 6!\]
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making \[k=8\times 7\] as per estudier
how you know 8time 7?
I don't understand
n! = n * (n-1)! Say if u understand or not...
yes I understand
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So 8! = 8*7!
so 8!= 8 time (8-1) ?
n! = n * (n-1)! so So 8! = 8*7! and 7! = 7* 6! Then u cancel the 6! top and bottom leaves 8*7
Do you see now?
yes
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i understand now
(8*7*6*5....)/(6*5*4...)
ahhh I see
we can write it all out yes? \[8!=8\times 7\times 6\times 5\times 4\times 3\times 2\times 1\] and \[6!=6\times 5\times 4\times 3\times 2\times 1\] so \[6! \times 8\times 7=8!\]
ok thanks
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i guess the answer is k=56
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