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Mathematics 18 Online
OpenStudy (anonymous):

What is √x√x√x ?

OpenStudy (anonymous):

\[x \sqrt{x}\]

OpenStudy (anonymous):

Or \[x ^{3/2}\]

OpenStudy (anonymous):

= x ^ ( 1/2 + 1/.2 + 1/2 ) = x ^ (3/2)

OpenStudy (anonymous):

Uh idk how to write it here but its like this √x is a root of x which is a root of √x.

OpenStudy (anonymous):

And the answer choices are x^7/8 x^7/4 x^15/16 x^3/4 and x^15/8

OpenStudy (anonymous):

\[\sqrt[x]{\sqrt[x]{x}}\] ?

OpenStudy (anonymous):

\begin{eqnarray*}\sqrt{x\sqrt{x\sqrt{x}}} &=& \left(x\left(x\left(x\right)^{1/2}\right)^{1/2}\right)^{1/2}\\&=&\left(x\left(x^{3/2}\right)^{1/2}\right)^{1/2}\\&=&\left(x\cdot x^{3/4}\right)^{1/2}\\&=&\left(x^{7/4}\right)^{1/2}\\&=&x^{7/8}.\end{eqnarray*}

OpenStudy (anonymous):

Inspired interpretation!

OpenStudy (anonymous):

Yea @krebante its like that ! thank you :D

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