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What is √x√x√x ?
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\[x \sqrt{x}\]
Or \[x ^{3/2}\]
= x ^ ( 1/2 + 1/.2 + 1/2 ) = x ^ (3/2)
Uh idk how to write it here but its like this √x is a root of x which is a root of √x.
And the answer choices are x^7/8 x^7/4 x^15/16 x^3/4 and x^15/8
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\[\sqrt[x]{\sqrt[x]{x}}\] ?
\begin{eqnarray*}\sqrt{x\sqrt{x\sqrt{x}}} &=& \left(x\left(x\left(x\right)^{1/2}\right)^{1/2}\right)^{1/2}\\&=&\left(x\left(x^{3/2}\right)^{1/2}\right)^{1/2}\\&=&\left(x\cdot x^{3/4}\right)^{1/2}\\&=&\left(x^{7/4}\right)^{1/2}\\&=&x^{7/8}.\end{eqnarray*}
Inspired interpretation!
Yea @krebante its like that ! thank you :D
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