Question

what number can be added to both the numerator and denominator of 16/37 to produce a fraction equal to 5/8?
can you please go step by step

Answer 1

\[\frac{16+x}{37+x} = \frac{5}{8}\]cross multiply to get\[8(16+x) = 5(37+x)\]\[128+8x = 185+5x\]\[3x=57\]\[x=19\]

Answer 2

Setup the problem first:
\[(16+x)/(37+x) = 5/8\]
Cross multiply:
\[8(16+x) = 5(37+x)\]
\[128+8x=185+5x\]
\[3x=57\]
\[x=19\]
Proof:
\[(16+19)/(37+19)=35/56=5/8\]