Question

27x^6-9x+21x^2/3x^2
divide

Answer 1

27x^6-9x+21x^2 3x(9x^5 - 3 + 7x) 9x^5 + 7x - 3
---------------- = ------------------ = --------------
3x^2 3x*x x

Answer 2

you dont missed anything ?

Answer 3

9x dont have exponent ?

Answer 4

long division with with polynomial functions. break it into parts.

27x^6/3x^2 = 9x^4

21x^2/3x^2 = 7

-9x/3x^2 = -9x/3x^2 <---this is the remainder value since 3x^2 doesn't go into 9x

so your quotient value is 9x^4+7-(9x/3x^2)

Answer 5

i lied 9x/3x^2 can be expressed as 3/x...duh

Answer 6

so I am a little confused going over these steps. where did the 7 go?