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x+5(2x-4)^-1 y and x intercepts
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(x+5)(2x-4)^-1
is this \[\frac{x+5}{2x-4}\]?
if so, y - intercept put x = 0 and get \[-\frac{5}{4}\]
x - intercept put y = 0 and solve \[0=\frac{x+5}{2x-4}\] aka \[x+5=0\] or \[x=-5\]
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