Question

Soybean meal is 16% protein, cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 13% protein?

Answer 1

that question makes almost no sense......

Answer 2

anyways, just multiply the decimal form of each value by the total weight and that will give you the individual weights for each ingredient

Answer 3

No im pretty much stumped from this

Answer 4

very,very,very easy let
x=16%= 0.16
let y=8%= 0.08
13%= 0.13
x+y= 320
y= 320 -x
0.16x+0.08y=320*0.13
Substitution : y= 320 -x
0,16x+0.08(320 -x )=320*0.13
here the equation , can u solve from here?

Answer 5

medal for help?

Answer 6

%13 can be written as .13
Ask yourself how much protien by mass is in the 360lb mix.
360(.13)=57.6
57.6lbs is your total.
The equation can be written (.16)s+(0.08)c=57.6
where s is soybeans and c is cornmeal.
Guess and check to determine that 260lbs of soybeans and 200lbs of cornmeal yields 57.6lbs of total protien

Answer 7

Oops I forgot your total must be 360lbs increase soybean mass nd decrease cornmeal mass...

Answer 8

0,16x+0.08(320 -x )=320*0.13
0,16x+25.6 -0.08x =41.6
0.08x=41.6-25.6
x=16/0.08
x= 200
Substitution : x= 20 solve for y
x+y= 320
200+y= 320
y = 320-200
y = 120
Soybean meal is 200 pounds
cornmeal is 120 pounds
check;
0.16(200)+0.08(120)=41.6
32+9.6 = 41.6
41.6= 41.6
0.16 or .16 , 0.13 or .13 , 0.08 or .08 is the same
320-lb mixture not 360 lb
I don't see that question makes no sense..

Answer 9

me it make sense

Answer 10

My answer make sense?