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OpenStudy (anonymous):
solve the equation:
log2 x=3
my answer is 8 is that correct?
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OpenStudy (anonymous):
yes!
OpenStudy (anonymous):
thanx and you are quick
OpenStudy (anonymous):
via
\[2^3=8\] so it is nice to be able to switch!
OpenStudy (anonymous):
you did the work. i just said "yes"
OpenStudy (anonymous):
one more \[\log_{5}125=x \]
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OpenStudy (anonymous):
i have 25
OpenStudy (anonymous):
switch!
OpenStudy (anonymous):
no rewrite in exponential form
OpenStudy (anonymous):
write this in exponential form and the answer will be obvious. and obviously not 25 which is way way too big
OpenStudy (anonymous):
k give me a sec
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OpenStudy (anonymous):
let me know what you get when you switch forms
OpenStudy (anonymous):
no cheating and looking at other post!
OpenStudy (anonymous):
3
OpenStudy (anonymous):
yes but i hope you realize why and why you need to be able to switch from one form to the other with ease
OpenStudy (anonymous):
takes two seconds to write
\[5^x=125\] and then figure x = 3
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OpenStudy (anonymous):
yes i am catching on but 9 years since any algebra doesnt make it very easy to come by....yes because 5^3 =125
OpenStudy (anonymous):
good
OpenStudy (anonymous):
not really much algebra to this yet though. just rewriting
OpenStudy (anonymous):
i guess
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