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solve for X... e^x-1-2.3 (this is a logarithm section of the book)
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\[e^{x-1}-2.3\]?
oops, that should read =2.3
\[e ^{x-1}=2.3\]
Take ln of both side ln e^(x-1)=ln (2.3) x-1=ln(2.3)
** ln and e cancel, leaving us with just (x-1)
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x=ln(2.3)+1
wait a sec... ln and e cancel???
yes, ln e = 1
I see... ok, thanks!
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