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last one for the night (I hope)... solve for X again: log(7x-2)-log(x-2)=1
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\[\log((7x-2)/(x-2))=1\]
raise both sides with a base of 10
\[(7x-2)/(x-2)=10\]
\[(x-2)*10=7x-2\]
x= 3 1/3
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Hmm, x should equal 6 I think
it is 6
10x - 20 = 7x - 2 3x = 18 x = 6
dr's process was right, the last calculation was the only thing off
excellent, thanks to all!
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shoot yes 20 -2 = 18 not 22 LOL
giving 6
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