Question

For the following equation, state the value of the discriminant and then describe the nature of the solutions. 15x^2-9x+3=0. What is the value of the discriminant?

Answer 1

The discriminant is b^2-4(a)(c),

So here a=15, b=-9, and c=3

Discriminant = (81)-4(15)(3)

Answer 2

-99

Answer 3

Since the discriminant is negative, there are no real solutions

Answer 4

Nature of solutions:
Discriminant = 0 -> one solution
Discriminant > 0 -> two solutions
Discriminant < 0 -> complex roots