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solve by factoring, then using zero product principle 12x-4=3x^3-x^2
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\[(2-x) (x+2) (3 x-1)=-3 x^3+x^2+12 x-4 \]
what is the integer?
The integer solution x=2 and x=-2 comes from the factors (2-x)(x+2). Set each factor to zero and solve for x. In a similar manner, x=1/3.
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