Question

help! qudratic formula for: (x+1)^2=2(x-1)^2

Answer 1

1. square each pair of parenthesis and then foil it out.
(x+1)(x+I)= 2(x-1)(x-1)
x^2+2x+1=2(x^2-2x+1)
2.distribute the 2
=2x^2-4x+2
3.since quadratics are equal to zero, put everything on one side and combine like terms.
0= -x^2-2x-1+2x^2-4x+2
0= x^2-6x+1
4. That's your quadratic