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Please help! If a varies jointly as b and c, and a=27 when b=18 and c=3, find a when b=6 and c=1/3.
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\[\frac{27}a{}=\frac{18*3}{6*(\frac{1}{3})}\]
can u solve now?
I think so. Thank you for the help!
Medal?
54/2=27? Now what?
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a=1
27a=27 a=27/27 a=1
Ohhh. I get it. Divide by 2. Thank you!
ty
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