Question

the length of a rectangle is twice the width.The area is 72yd^2.Find the length and width.

Answer 1

\[x \times 2x =72 yd ^{2} \]
\[2x ^{2 }= 72 yd ^{2}\]
\[x^{2}=36 \rightarrow x=6\]
length= 12 and width=6 yd