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Mathematics 19 Online
OpenStudy (anonymous):

Please help look at link to view problem

OpenStudy (anonymous):

OpenStudy (anonymous):

plug in 100, 200, and 400 for P(t) and solve for t each time

OpenStudy (anonymous):

100=40e^(.02*t) 2.5=e^(.02*t) ln(2.5)=ln(e^(.02t) .91629=.02*t t=45.8 years since 1990 so the population will be at 100 million in 2035 repeat this for P(t)=200 and 400

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