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OpenStudy (anonymous):
2x^3+3x^2-32x-48
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OpenStudy (anonymous):
2x^3+3x^2-32x-48=0 2x^3+3x^2=32x+48 x^2(2x+3)=16(2x+3) x^2=16*[(2x+3)/(2x+3)] <- the fraction will reduce to 1 because its the same on top and bottom X=sqrt(16) x=4
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