Question

\[c/9^2 \div c^2/9^3\]
divide and simplify.

Answer 1

we change the operation from divide to multiply and flip the second fraction over (i.e. take its inverse)

c 9^3
--- * -----
9^2 c^2

Now cancelling out common factors from numerator and denominator, we get

9
----
c

Answer 2

so you flip it and then cancel out ?

Answer 3

c/9^2/c^2/9^3=c/9^2 * 9^3/c^2 = 9/c

Answer 4

harkirat it says incorrect?

Answer 5

you know why it is totally my fault. it is a not 9

Answer 6

so I changed the answer to a/c and it was correct! I am so sorry.

Answer 7

so it was a and not 9????

Answer 8

yea! When I wrote the problem down it I made the stem too long on the a!

Answer 9

:))
no problem....