Question

Solve the following inequality : 10 + 3 (2x - 6) ≤ 4 (2x - 7).

a. x ≤ 1
b. x ≤ -10/7
c. x ≤ -10
d. x ≥ 10

Answer 1

remember to switch the inequality when you multiply or divide by a neg number.
so:\[10 + 3(2x-6)\le4(2x-7)\]
\[10+6x-18\le8x-28\]
\[-8\le2x-28\]
\[20\le2x\]
\[x \ge10\]