solve the equation for x. don not include "x=" in your answer log[4}^x=3/2
5^x=24 x log5=log 24 x=log 24/ log 5 use your calculator x=1.97 5^1.97=23.82 ^_^ to make sure we check it hope it helps!
don't you rewrite the logarithmic equation into an exponential equation in order to find x
It depends... i'm not that sure but you probly can
\[log_ba = k \iff b^k = a\] Therefore \[log_4x = \frac{3}{2} \iff4^\frac{3}{2} = x\]\[\implies x = (2^2)^\frac{3}{2}\]\[=2^3\]\[ = 8\]
lol do not include x= in your answer? who says that?
She's doing an online class where she submits the answers to a website, and that is probably the instructions for the problem..
oh that makes sense lol
Ahh!! your right nvm about my answer ...
To tell you the truth my friend is over and she and I tired solving this... and it didnt come out right sorry... we should rethink our thoughts before we blurt out some nonsence
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