Question

Find the oblique asymptote.

(x^2-4x-5)/(x-3)

Answer 1

3| 1 -4 -5
| 3 -3
| _____________
1 -1 | -8

so we have
\[\frac{x^2-4x-5}{x-3}=x-1+\frac{-8}{x-3}\]
so y=x-1 is the slant asymptote