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OpenStudy (saifoo.khan):
|x-8| > 22 |x-8| < -22
OpenStudy (saifoo.khan):
Joathday, am i correct?
OpenStudy (anonymous):
noo,,
OpenStudy (saifoo.khan):
Oh, where did i go wrong?
OpenStudy (anonymous):
when u split the equation u take away the absolute value. other than that its fine just not finished
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OpenStudy (anonymous):
Question: 18 of 20: Solve the inequality: Select one of the options below as your answer: A. x > -30 or x < -14 B. x > 30 or x < -14 C. x > 30 or x < 14 D. x > 30 and x < -14
OpenStudy (saifoo.khan):
Ok, so its like this:
x-8 > 22 x-8 < -22
OpenStudy (anonymous):
x>30 or x<-14
and yes
OpenStudy (saifoo.khan):
its B
OpenStudy (saifoo.khan):
right?
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OpenStudy (saifoo.khan):
Yeas, it is! :D
OpenStudy (anonymous):
yup!
OpenStudy (anonymous):
Which number line represents the solution set of the equation Select one of the options below as your answer |x+6|=2 where would the point go
OpenStudy (saifoo.khan):
x = -4, i guess.
OpenStudy (anonymous):
x=-8,-4
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OpenStudy (anonymous):
Use the quadratic formula to solve the quadratic equation: 2x2 − 3x − 7 = 0
OpenStudy (saifoo.khan):
Alright, got that! ^.^
OpenStudy (anonymous):
\[(3\pm \sqrt{65})/4\]
OpenStudy (anonymous):
i dont have a calculator with me so thats the best im gonna do
OpenStudy (anonymous):
thanks is it + eqals to or just +
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OpenStudy (anonymous):
its plus or minus which means there is possibly two answers. in 1 equation u have to add them and in another u have to subtract. i would check it for u if i had a cal but sadly i wont have it for another hour as my brother uses it