Question

Patrick throws a ball in the air. The height h in feet of the ball after t seconds is h=4+60t-16t^2. After how many seconds is the ball 60 feet above the ground.

Answer 1

so we should set the height = to 60, and solve for t:
\[60 = 4+60t-16t^2 \Rightarrow -56+60t-16t^2 = 0\]
you just want to use the quadratic formula to pop out the answer.

Answer 2

sorry but idk how to use that formula sorry

Answer 3

then learn

Answer 4

t=1.75
t=2

Answer 5

\[(-b \pm \sqrt{b^2-4ac})/(2a) \]
for when its written as ax^2 + bx+c