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Mathematics 23 Online
OpenStudy (anonymous):

Can anybody answer this? What is the fewest number of marbles that Jeff could have? Here are the clues: When he puts them in groups of 3, there are no marbles remaining. When he puts them in groups of 2 or 5, there is one marble left

OpenStudy (anonymous):

21?

OpenStudy (anonymous):

thats right how did you do that?

OpenStudy (anonymous):

Went up by multiples of 3 until I found one that worked

OpenStudy (anonymous):

thanks

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