Question

2-(a-15/a+5) = (a^-5/a+5)

Answer 1

Do you mean:
\[2-\frac{a-15}{a+5}=\frac{a^{-5}}{a+5}\]
If so, then:
\[\frac{2(a+5)}{a+5}-\frac{a-15}{a+5}=\frac{a^{-5}}{a+5}\]
\[\frac{a+25}{a+5}=\frac{a^{-5}}{a+5}\Rightarrow a+25=a^{-5}\]
\[a^{-5}-a=25\]
I'd need a calc to solve from here.